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MCQMediumJEE Main 2025 · 24 January, Shift 1Linear Differential Equations

Mathematics Question from JEE Main 2025 · 24 January, Shift 1

Let y=y(x)y = y(x) be the solution of the differential equation (xy−5x21+x2)dx+(1+x2)dy=0,y(0)=0.\left( xy - 5x^2 \sqrt{1 + x^2} \right) dx + (1 + x^2) dy = 0, \quad y(0) = 0. Then y(3)y(\sqrt{3}) is equal to:

  • A

    532\frac{5\sqrt{3}}{2}

  • B

    143\sqrt{\frac{14}{3}}

  • C

    222\sqrt{2}

  • D

    152\sqrt{\frac{15}{2}}

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