JEE Chemistry 2025 Question with Solution

Given: The reaction sequence involves diazotization conditions with $NaNO_2$ and $HCl$ at $0-5^\circ C$. The molecular formula of [A] is C₁₄H₁₄N₂O₂ and the molecular formula of [C] is C₁₆H₁₈N₂O₂.

Find: The total number of sp³ hybridized carbon atoms in the major product [C].

The extracted solution states that the final major product [C] contains 4 sp³ hybridized carbon atoms.

The solution approach is based on counting carbons connected through single bonds in the final product structure. From the molecular understanding described in the solution, the total number of sp³ hybridized carbons in [C] is 4.

Therefore, the correct option is C.

Given: The sequence starts with diazotization and subsequent conversion steps.

Find: Number of sp³ carbons in major product [C].

The solution describes:

1. Reaction Analysis: the sequence suggests diazotization of an amine-containing substrate.
2. Structure Clue from [A]: [A] has formula C₁₄H₁₄N₂O₂.
3. Final Product Clue: [C] has formula C₁₆H₁₈N₂O₂.
4. Hybridization Count: the final structure is interpreted to contain 4 carbons with sp³ hybridization.

Thus, the total number of sp³ hybridized carbon atoms in [C] is 4, so the correct option is C.

Note: The solution gives the final count directly but does not supply a fully explicit structural derivation for [C].