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MCQEasyJEE Main 2025 · 23 January, Shift 1Mole Concept

Chemistry Question from JEE Main 2025 · 23 January, Shift 1

2.8×10−32.8 \times 10^{-3} mol of CO2CO_2 is left after removing 102110^{21} molecules from its ‘xx’ mg sample. The mass of CO2CO_2 taken initially is:

Given: NA=6.02×1023 mol−1N_A = 6.02 \times 10^{23} \, mol^{-1}

  • A

    196.2 mg196.2 \, \text{mg}

  • B

    98.3 mg98.3 \, \text{mg}

  • C

    150.4 mg150.4 \, \text{mg}

  • D

    48.2 mg48.2 \, \text{mg}

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