CrCl₃.xNH₃ can exist as a complex. 0.1 molal aqueous solution of this complex shows a depression in freezing p…

Question

CrCl$$_3$$.xNH$$_3$$ can exist as a complex. **$$0.1$$ molal** aqueous solution of this complex shows a depression in freezing point of **$$0.558^\circ 	ext{C}$$**. Assuming **$$100\%$$** ionization of this complex and coordination number of **Cr** is **$$6$$**, the complex will be:

(Given $$K_f = 1.86 \, 	ext{K kg mol}^{-1}$$)

Accepted Answer

C. [Cr(NH$$_3$$)$$_5$$Cl]Cl$$_2$$

Answer

A. [Cr(NH$$_3$$)$$_6$$]Cl$$_3$$

Answer

B. [Cr(NH$$_3$$)$$_4$$Cl$$_2$$]Cl

Answer

D. [Cr(NH$$_3$$)$$_3$$Cl$$_3$$]

Answer & step-by-step solution

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