Given: A circuit with a battery of 6V and three resistors of 4Ω each is shown. We must check which observations among A, B, C, D, E are correct.
Find: The correct option.
From the solution, the intended analysis is to use series-parallel reduction and Ohm's law.
The stated working says that two resistors combine in series to give
Rseries=4+4=8Ω
and this is taken in parallel with another 4Ω resistor, so
Rparallel=81+411=38Ω
Then another 4Ω resistor is added in series, giving
Rtotal=4+38=320Ω≈6.67Ω