MCQEasyJEE Main 2025 · 23 January, Shift 1Dimensions & Dimensional Analysis

Physics Question from JEE Main 2025 · 23 January, Shift 1

The position of a particle moving on xx-axis is given by x(t)=Asint+Bcos2t+Ct2+Dx(t) = A \sin t + B \cos^2 t + Ct^2 + D, where tt is time. The dimension of ABCD\frac{ABC}{D} is:

  • A

    LL

  • B

    L3T2L^3 T^{-2}

  • C

    L2T2L^2 T^{-2}

  • D

    L2L^2

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