Let . The number of relations on , containing and , which are reflexive and transitive but not symmetric, is _____.
JEE Mathematics 2025 Question with Solution
Answer
Correct answer:7
Step-by-step solution
Standard Method
Given: . The relation on contains and , and it must be reflexive, transitive, but not symmetric.
Find: The number of such relations.
A reflexive relation on must contain
Since and are given, transitivity forces
because
So the minimal relation is
Now the only possible additional reverse pairs are
We check which subsets of these can be added while preserving transitivity.
Valid transitive extensions are:
- No additional pair
The pair combination and together forces by transitivity, so that case is already included only in the seventh relation.
Each of these relations is not symmetric, because at least one of does not have its reverse pair present in full.
Therefore, the number of required relations is .
Casewise Counting
Given: and the relation contains and .
Find: Count all relations that are reflexive, transitive, and not symmetric.
Reflexive means all diagonal pairs must be present:
Transitivity with the given pairs gives:
Hence every valid relation must contain
Now consider the optional reverse pairs:
Check all transitive possibilities:
- Add none: valid.
- Add only : valid.
- Add only : valid.
- Add only : valid.
- Add and : valid.
- Add and : valid.
- Add and : then transitivity requires , so this is not a separate case.
- Add all three: valid.
Thus the total number of valid relations is
Also, none of these relations is symmetric, because symmetry would require all reverse pairs of the non-diagonal elements, which does not happen here.
Therefore, the answer is .
Common mistakes
Including only the reflexive pairs and the given pairs, but forgetting that transitivity from and forces . This makes the relation incomplete. Always add every pair required by transitivity before counting cases.
Treating and as independently optional without checking transitivity. If both are included, then and force . So those two cannot be counted as a separate valid case unless is also present.
Misreading 'not symmetric' as meaning that no reverse pair can be present at all. That is incorrect. 'Not symmetric' only means at least one pair lacks its reverse. Some reverse pairs may still be included, provided the whole relation does not become symmetric.
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