MCQMediumJEE Main 2025 · 22 January, Shift 2Applications of Integrals (Area)

Mathematics Question from JEE Main 2025 · 22 January, Shift 2

The area of the region enclosed by the curves y=x24x+4y = x^2 - 4x + 4 and y2=168xy^2 = 16 - 8x is:

  • A

    43\frac{4}{3}

  • B

    88

  • C

    83\frac{8}{3}

  • D

    55

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