Consider the following sequence of reactions :
Molar mass of the product formed (A) is _____ g mol $^{-1}$ .

Question

Consider the following sequence of reactions: Molar mass of the product formed (A) is g mol^-1.

Accepted Answer

Given: A reaction sequence is shown, and the molar mass of product A is to be found.

Find: The molar mass of product A in g mol $^{-1}$ .

From the solution, the final product A has molecular formula $\mathrm{C_8H_{10}O_3}$ .

Using atomic masses:

\begin{aligned} \text{C} &= 12.011 \, \text{g mol}^{-1} \\ \text{H} &= 1.008 \, \text{g mol}^{-1} \\ \text{O} &= 16.00 \, \text{g mol}^{-1} \end{aligned}

Now compute the molar mass contribution of each element:

\begin{aligned} \text{Mass from C} &= 8 \times 12.011 = 96.088 \, \text{g mol}^{-1} \\ \text{Mass from H} &= 10 \times 1.008 = 10.080 \, \text{g mol}^{-1} \\ \text{Mass from O} &= 3 \times 16.00 = 48.000 \, \text{g mol}^{-1} \end{aligned}

Adding these:

M = 96.088 + 10.080 + 48.000 = 154.168 \, \text{g mol}^{-1}

Rounding to the nearest whole number, the molar mass is $154 \, \text{g mol}^{-1}$ . Therefore, the correct option is A.

Given: The reaction sequence leads to product A.

Find: Its molar mass.

The available solution states that after identifying the final structure from the figure, product A is assigned the formula $\mathrm{C_8H_{10}O_3}$ .

The molar mass is obtained by summing atomic masses according to the subscripts:

M = 8(M_{\mathrm{C}}) + 10(M_{\mathrm{H}}) + 3(M_{\mathrm{O}})

Substitute standard atomic masses:

M = 8(12.011) + 10(1.008) + 3(16.00)

M = 96.088 + 10.080 + 48.000

M = 154.168 \, \text{g mol}^{-1}

Thus, the molar mass of the product formed is $154 \, \text{g mol}^{-1}$ , so the correct option is A.

Answer