Arrange the following solutions in order of their increasing boiling points.
(i) M NaCl (ii) M Urea
(iii) M NaCl (iv) M NaCl
- A
((ii) < (i) < (iii) < (iv))
- B
((ii) < (i) = (iii) < (iv))
- C
((i) < (ii) < (iii) < (iv))
- D
((iv) < (iii) < (i) < (ii))
Arrange the following solutions in order of their increasing boiling points.
(i) M NaCl (ii) M Urea
(iii) M NaCl (iv) M NaCl
((ii) < (i) < (iii) < (iv))
((ii) < (i) = (iii) < (iv))
((i) < (ii) < (iii) < (iv))
((iv) < (iii) < (i) < (ii))
Correct answer:A
Standard Method
Given: The solutions are (i) M NaCl, (ii) M urea, (iii) M NaCl, and (iv) M NaCl.
Find: The order of increasing boiling points.
Boiling point elevation is a colligative property and depends on the number of solute particles present. The relation is
where is the van't Hoff factor.
For the given solutions:
For very dilute solutions, compare concentration:
As boiling point increases with increasing value of concentration, the order is:
Therefore, the correct option is A.
Assuming only concentration matters. This is wrong because boiling point elevation depends on the total number of solute particles. Include the van't Hoff factor along with concentration.
Treating NaCl and urea as equivalent at the same concentration. This is wrong because NaCl dissociates into ions while urea does not. Compare concentration, not concentration alone.
Using the higher concentration order correctly but placing (i) and (ii) together. This is wrong because even at the same M concentration, NaCl gives more particles than urea. Hence (ii) must come before (i).
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