A parallel-plate capacitor of capacitance 40 μ F is connected to a 100 V power supply. Now the intermediate sp…

Question

A parallel-plate capacitor of capacitance $40\,\mu \text{F}$ is connected to a $100\,\text{V}$ power supply. Now the intermediate space between the plates is filled with a dielectric material of dielectric constant $K = 2$ . Due to the introduction of dielectric material, the extra charge and the change in the electrostatic energy in the capacitor, respectively, are -

A
$2\,\text{mC}$ and $0.2\,\text{J}$
B
$8\,\text{mC}$ and $2.0\,\text{J}$
C
$4\,\text{mC}$ and $0.2\,\text{J}$
D
$2\,\text{mC}$ and $0.4\,\text{J}$

Accepted Answer

C. **$$4\,	ext{mC}$$** and **$$0.2\,	ext{J}$$**

Answer

A. **$$2\,	ext{mC}$$** and **$$0.2\,	ext{J}$$**

Answer

B. **$$8\,	ext{mC}$$** and **$$2.0\,	ext{J}$$**

Answer

D. **$$2\,	ext{mC}$$** and **$$0.4\,	ext{J}$$**

Answer & step-by-step solution

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