MCQMediumJEE Main 2025 · 22 January, Shift 1Linear Differential Equations

Mathematics Question from JEE Main 2025 · 22 January, Shift 1

Let x=x(y)x = x(y) be the solution of the differential equation y2dx+(x1y)dy=0y^2 \, dx + \left( x - \frac{1}{y} \right) dy = 0. If x(1)=1x(1) = 1, then x(12)x\left( \frac{1}{2} \right) is :

  • A

    12+e\frac{1}{2} + e

  • B

    32+e\frac{3}{2} + e

  • C

    3e3 - e

  • D

    3+e3 + e

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