MCQMediumJEE Main 2024 · 9 April, Shift 2Conic Sections (Parabola, Ellipse, Hyperbola)

Mathematics Question from JEE Main 2024 · 9 April, Shift 2

Let the foci of a hyperbola HH coincide with the foci of the ellipse EE: (x1)2100+(y1)275=1\frac{(x-1)^2}{100} + \frac{(y-1)^2}{75} = 1, and the eccentricity of the hyperbola HH be the reciprocal of the eccentricity of the ellipse EE. If the length of the transverse axis of HH is α\alpha and the length of its conjugate axis is β\beta, then 3α2+2β23\alpha^2 + 2\beta^2 is equal to:

  • A

    242242

  • B

    225225

  • C

    237237

  • D

    205205

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