Let ∫₀^x √(1 - (y'(t))²) dt = ∫₀^x y(t) dt, 0 ≤ x ≤ 3, y ≥ 0, y(0… | JEE Main 2024 Mathematics PYQ

MCQMediumJEE Main 2024 · 9 April, Shift 2Linear Differential Equations

Let $\int_{0}^{x} \sqrt{1 - (y'(t))^2} \, dt = \int_{0}^{x} y(t) \, dt$ , $0 \leq x \leq 3$ , $y \geq 0$ , $y(0) = 0$ . Then at $x = 2$ , $y'' + y + 1$ is equal to:

A
$1$
B
$2$
C
$\sqrt{2}$
D
$\frac{1}{2}$

Answer & step-by-step solution

Practice more Linear Differential Equations questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Start free trial More on Linear Differential Equations

Answer & step-by-step solution

Practice more Linear Differential Equations questions

Related questions