The parabola y² = 4x divides the area of the circle x² + y² = 5 i… | JEE Main 2024 Mathematics PYQ | Jeeify

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MCQMediumJEE Main 2024 · 9 April, Shift 1Conic Sections (Parabola, Ellipse, Hyperbola)

The parabola $y^2 = 4x$ divides the area of the circle $x^2 + y^2 = 5$ in two parts. The area of the smaller part is:

A
$\frac{2}{3} + 5\sin^{-1}\left(\frac{2}{\sqrt{5}}\right)$
B
$\frac{1}{3} + 5\sin^{-1}\left(\frac{2}{\sqrt{5}}\right)$
C
$\frac{1}{3} + \sqrt{5}\sin^{-1}\left(\frac{2}{\sqrt{5}}\right)$
D
$\frac{2}{3} + \sqrt{5}\sin^{-1}\left(\frac{2}{\sqrt{5}}\right)$

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