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MCQMediumJEE Main 2024 · 8 April, Shift 2Nature of Roots & Formation of Equations

Mathematics Question from JEE Main 2024 · 8 April, Shift 2

Let α,β;α>β,\alpha, \beta; \alpha > \beta, be the roots of the equation x2−2x−3=0.x^2 - \sqrt{2}x - \sqrt{3} = 0. Let Pn=αn−βn,n∈N.P_n = \alpha^n - \beta^n, n \in N. Then (113−102)P10+(112+10)P11−11P12(11\sqrt{3} - 10\sqrt{2})P_{10} + (11\sqrt{2} + 10)P_{11} - 11P_{12} is equal to:

  • A

    102P910\sqrt{2}P_9

  • B

    103P910\sqrt{3}P_9

  • C

    112P911\sqrt{2}P_9

  • D

    113P911\sqrt{3}P_9

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