MCQMediumJEE Main 2024 · 8 April, Shift 2Determinants Basics

Mathematics Question from JEE Main 2024 · 8 April, Shift 2

If αa\alpha \ne a, βb\beta \ne b, γc\gamma \ne c and

αbcaβcabγ=0\left|\begin{matrix}\alpha & b & c \\ a & \beta & c \\ a & b & \gamma\end{matrix}\right| = 0

then:

aαa+bβb+γγc\frac{a}{\alpha-a}+\frac{b}{\beta-b}+\frac{\gamma}{\gamma-c}

is equal to:

  • A

    22

  • B

    33

  • C

    00

  • D

    11

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