Let P(x, y, z) be a point in the first octant, whose projection in the xy-plane is the point Q. Let OP = γ, th…

Question

Let $$P(x, y, z)$$ be a point in the first octant, whose projection in the $$xy$$-plane is the point $$Q$$. Let $$OP = \gamma$$, the angle between $$OQ$$ and the positive $$x$$-axis be $$	heta$$, and the angle between $$OP$$ and the positive $$z$$-axis be $$\phi$$, where $$O$$ is the origin. Then the distance of $$P$$ from the $$x$$-axis is:

Accepted Answer

A. $$\gamma\sqrt{(1 - \sin^2(\phi) \cos^2(	heta))}$$

Answer

B. $$\gamma\sqrt{(1 + \cos^2(	heta) \sin^2(\phi))}$$

Answer

C. $$\gamma\sqrt{(1 - \sin^2(	heta) \cos^2(\phi))}$$

Answer

D. $$\gamma\sqrt{(1 + \cos^2(\phi) \sin^2(	heta))}$$

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