MCQMediumJEE Main 2024 · 6 April, Shift 2Basics: Distance, Section Formula, Locus

Mathematics Question from JEE Main 2024 · 6 April, Shift 2

If the locus of the point, whose distances from the point (2,1)(2, 1) and (1,3)(1, 3) are in the ratio 5:45:4, is ax2+by2+cxy+dx+ey+170=0ax^2 + by^2 + cxy + dx + ey + 170 = 0, then the value of a2+2b+3c+4d+ea^2 + 2b + 3c + 4d + e is equal to:

  • A

    55

  • B

    2727

  • C

    3737

  • D

    437437

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