MCQEasyJEE Main 2024 · 6 April, Shift 1Characteristics of EM Waves

Physics Question from JEE Main 2024 · 6 April, Shift 1

The magnetic field in a plane electromagnetic wave is:

By=(3.5×107)sin(1.5×103x+0.5×1011t)TB_y = (3.5 \times 10^{-7}) \sin(1.5 \times 10^3 x + 0.5 \times 10^{11} t) \, \text{T}. The corresponding electric field will be:

  • A

    Ey=1.17sin(1.5×103x+0.5×1011t)V/mE_y = 1.17 \sin(1.5 \times 10^3 x + 0.5 \times 10^{11} t) \, \text{V/m}

  • B

    Ez=105sin(1.5×103x+0.5×1011t)V/mE_z = 105 \sin(1.5 \times 10^3 x + 0.5 \times 10^{11} t) \, \text{V/m}

  • C

    Ez=1.17sin(1.5×103x+0.5×1011t)V/mE_z = 1.17 \sin(1.5 \times 10^3 x + 0.5 \times 10^{11} t) \, \text{V/m}

  • D

    Ey=10.5sin(1.5×103x+0.5×1011t)V/mE_y = 10.5 \sin(1.5 \times 10^3 x + 0.5 \times 10^{11} t) \, \text{V/m}

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