MCQMediumJEE Main 2024 · 6 April, Shift 1Linear Differential Equations

Mathematics Question from JEE Main 2024 · 6 April, Shift 1

If logey=3sin1x\log_e y = 3\sin^{-1} x, then (1x2)yxy(1 - x^2) y'' - x y' at x=12x = \frac{1}{2} is equal to:

  • A

    9eπ/69e^{\pi/6}

  • B

    3eπ/63e^{\pi/6}

  • C

    3eπ/23e^{\pi/2}

  • D

    9eπ/29e^{\pi/2}

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