MCQMediumJEE Main 2024 · 6 April, Shift 1Determinants Basics

Mathematics Question from JEE Main 2024 · 6 April, Shift 1

For α,βR\alpha, \beta \in R and a natural number nn, let Ar=A_r =

r1n22+α2r2n2β3r23n(3n1)2\begin{vmatrix} r & 1 & \frac{n^2}{2} + \alpha \\ 2r & 2 & n^2 - \beta \\ 3r - 2 & 3 & \frac{n(3n - 1)}{2} \end{vmatrix}

Then 2A10A82A_{10} - A_8 is:

  • A

    4α+2β4\alpha + 2\beta

  • B

    2α+4β2\alpha + 4\beta

  • C

    2n2n

  • D

    00

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