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MCQMediumJEE Main 2024 · 5 April, Shift 2Linear Differential Equations

Mathematics Question from JEE Main 2024 · 5 April, Shift 2

The differential equation of the family of circles passing the origin and having the center on the line y=xy = x is:

  • A

    (x2−y2+2xy)dx=(x2−y2−2xy)dy(x^2 - y^2 + 2xy)dx = (x^2 - y^2 - 2xy)dy

  • B

    (x2+y2+2xy)dx=(x2+y2−2xy)dy(x^2 + y^2 + 2xy)dx = (x^2 + y^2 - 2xy)dy

  • C

    (x2−y2−2xy)dx=(x2−y2+2xy)dy(x^2 - y^2 - 2xy)dx = (x^2 - y^2 + 2xy)dy

  • D

    (x2+y2−2xy)dx=(x2+y2+2xy)dy(x^2 + y^2 - 2xy)dx = (x^2 + y^2 + 2xy)dy

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