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MCQMediumJEE Main 2024 · 4 April, Shift 1Conic Sections (Parabola, Ellipse, Hyperbola)

Mathematics Question from JEE Main 2024 · 4 April, Shift 1

The vertices of a triangle are A(−1,3-1, 3), B(−2,2-2, 2), and C(3,−13, -1). A new triangle is formed by shifting the sides of the triangle one unit inwards. Then the equation of the side of the new triangle nearest to the origin is:

  • A

    x−y−(2+2)=0x - y - (2 + \sqrt{2}) = 0

  • B

    −x+y−(2−2)=0-x + y - (2 - \sqrt{2}) = 0

  • C

    x+y−(2−2)=0x + y - (2 - \sqrt{2}) = 0

  • D

    x+y+(2−2)=0x + y + (2 - \sqrt{2}) = 0

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