MCQMediumJEE 2024Measures of Dispersion

JEE Mathematics 2024 Question with Solution

Let the median and the mean deviation about the median of 77 observations 170170, 125125, 230230, 190190, 210210, aa, bb be 170170 and 2057\frac{205}{7} respectively. Then the mean deviation about the mean of these 77 observations is:

  • A

    3131

  • B

    2828

  • C

    3030

  • D

    3232

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: The median of the 77 observations is 170170 and the mean deviation about the median is 2057\frac{205}{7}.

Find: The mean deviation about the mean.

Arrange the observations in ascending order using the median condition:

125, a, b, 170, 190, 210, 230125,\ a,\ b,\ 170,\ 190,\ 210,\ 230

Using mean deviation about median 170170,

0+45+60+20+40+170a+170b7=2057\frac{0 + |45| + |60| + |20| + |40| + |170-a| + |170-b|}{7} = \frac{205}{7}

So,

45+60+20+40+170a+170b=20545 + 60 + 20 + 40 + |170-a| + |170-b| = 205 170a+170b=40|170-a| + |170-b| = 40

From the ordering, a,b170a,b \le 170, hence

(170a)+(170b)=40(170-a) + (170-b) = 40 a+b=300a+b = 300

Now the mean is

xˉ=125+a+b+170+190+210+2307\bar{x} = \frac{125 + a + b + 170 + 190 + 210 + 230}{7}

Substituting a+b=300a+b=300,

xˉ=125+300+170+190+210+2307=175\bar{x} = \frac{125 + 300 + 170 + 190 + 210 + 230}{7} = 175

The mean deviation about the mean 175175 is

125175+a175+b175+170175+190175+210175+2301757\frac{|125-175| + |a-175| + |b-175| + |170-175| + |190-175| + |210-175| + |230-175|}{7}

Since the observations become 125,130,170,170,190,210,230125,130,170,170,190,210,230, this is

50+45+5+5+15+35+557=2107=30\frac{50 + 45 + 5 + 5 + 15 + 35 + 55}{7} = \frac{210}{7} = 30

Therefore, the mean deviation about the mean is 3030. The correct option is C.

Step-by-step working

Given: Observations are 170,125,230,190,210,a,b170, 125, 230, 190, 210, a, b. Median is 170170 and mean deviation about median is 2057\frac{205}{7}.

Find: Mean deviation about the mean.

Since there are 77 observations, the median is the 4th observation after arranging them in ascending order. Hence the ordered data can be written as

125, 130, 170, 170, 190, 210, 230125,\ 130,\ 170,\ 170,\ 190,\ 210,\ 230

after determining the unknown values.

Use the mean deviation about median:

17[125170+130170+170170+170170+190170+210170+230170]=2057\frac{1}{7}\left[|125-170| + |130-170| + |170-170| + |170-170| + |190-170| + |210-170| + |230-170|\right] = \frac{205}{7}

This gives

45+40+0+0+20+40+60=20545 + 40 + 0 + 0 + 20 + 40 + 60 = 205

which is satisfied, so the unknown value below 170170 is 130130 and the other is 170170.

Now compute the mean:

xˉ=125+130+170+170+190+210+2307=12257=175\bar{x} = \frac{125 + 130 + 170 + 170 + 190 + 210 + 230}{7} = \frac{1225}{7} = 175

Mean deviation about the mean 175175 is

17[125175+130175+170175+170175+190175+210175+230175]\frac{1}{7}\left[|125-175| + |130-175| + |170-175| + |170-175| + |190-175| + |210-175| + |230-175|\right] =17[50+45+5+5+15+35+55]= \frac{1}{7}\left[50 + 45 + 5 + 5 + 15 + 35 + 55\right] =2107=30= \frac{210}{7} = 30

Therefore, the mean deviation about the mean is 3030.

Common mistakes

  • Assuming aa and bb can be placed anywhere without using the median condition. This is wrong because for 77 observations, the 4th term in sorted order must be 170170. Always arrange the data first before applying deviation formulas.

  • Using mean deviation about the median incorrectly by omitting absolute values. This is wrong because positive and negative deviations would cancel. Always compute mean deviation with xiM|x_i - M|.

  • Calculating the arithmetic mean directly from the unsimplified list and forgetting to use the relation obtained from the median deviation. This is wrong because a+ba+b must first be determined. Use that relation before finding xˉ\bar{x}.

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