MCQEasyJEE Main 2024 · 31 January, Shift 1Dimensions & Dimensional Analysis

Physics Question from JEE Main 2024 · 31 January, Shift 1

A force is represented by F=ax2+bt1/2F = ax^2 + bt^{1/2} where xx = distance and tt = time. The dimensions of b2a\frac{b^2}{a} are:

  • A

    [ML3T3][ML^3T^{-3}]

  • B

    [MLT2][MLT^{-2}]

  • C

    [ML1T1][ML^{-1}T^{-1}]

  • D

    [ML2T3][ML^{2}T^{-3}]

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