MCQEasyJEE Main 2024 · 31 January, Shift 1Prisms & Total Internal Reflection

Physics Question from JEE Main 2024 · 31 January, Shift 1

The refractive index of a prism with apex angle AA is cot(A2)\cot\left(\frac{A}{2}\right). The angle of minimum deviation is:

  • A

    δm=180A\delta_m = 180^\circ - A

  • B

    δm=1803A\delta_m = 180^\circ - 3A

  • C

    δm=1804A\delta_m = 180^\circ - 4A

  • D

    δm=1802A\delta_m = 180^\circ - 2A

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