In the expansion of (1 + x)(1 - x²)(1 + 3/x + 3/x² + 1/x³)⁵, x ≠… | JEE Main 2024 Mathematics PYQ

MCQMediumJEE Main 2024 · 31 January, Shift 1Binomial Expansion

In the expansion of $(1 + x)\left(1 - x^2\right)\left(1 + \frac{3}{x} + \frac{3}{x^2} + \frac{1}{x^3}\right)^5$ , $x \ne 0$ , the sum of the coefficient of $x^3$ and $x^{-13}$ is equal to:

A
$118$
B
$108$
C
$125$
D
$130$

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