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NVAEasyJEE 2024Aldehydes & Ketones

JEE Chemistry 2024 Question with Solution

The compound formed by the reaction of ethanol with semicarbazide contains number of nitrogen atoms.

Answer

Correct answer:3

Step-by-step solution

Standard Method

Given: The reaction between ethanol and semicarbazide is considered.

Find: The number of nitrogen atoms in the compound formed.

The reaction shown is

CH3−CH=O+H2N−NH−C(=O)−NH2→CH3−CH=N−NH−C(=O)−NH2CH_3 - CH = O + H_2N - NH - C(= O) - NH_2 \rightarrow CH_3 - CH = N - NH - C(= O) - NH_2

In the product CH3−CH=N−NH−C(=O)−NH2CH_3 - CH = N - NH - C(= O) - NH_2, the nitrogen atoms are present as:

  1. =N=N
  2. −NH−-NH-
  3. −NH2-NH_2

Therefore, the compound contains 33 nitrogen atoms.

Common mistakes

  • Counting nitrogen atoms in semicarbazide before product formation instead of counting them in the final compound is incorrect. Always identify the product first and then count the nitrogen atoms present in that product.

  • Treating ethanol as the reacting carbonyl compound is conceptually wrong because the solution shows ethanal reacting with semicarbazide. Use the structure given in the reaction and count nitrogen atoms from the displayed product.

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