Given: Two statements about the confirmatory test for sulphide ion are to be checked.
Find: Which option correctly describes the truth values of Statement-I and Statement-II.
This is a qualitative analysis question based on the reaction of sulphide salts with dilute acid and the effect of the liberated gas on lead acetate paper.
For a sulphide ion, warming with dilute acid liberates hydrogen sulphide gas:
S2−+2H+⟶H2S
The liberated H2S reacts with lead acetate to form black lead sulphide:
H2S+Pb(CH3COO)2⟶PbS↓+2CH3COOH
So, the blackening of lead acetate paper is indeed a confirmatory test for sulphide ion. Therefore, Statement-I is true.
Now check Statement-II using the product formed in the reaction above. The black compound is lead sulphide, PbS. Hence the explanation that the paper turns black because of formation of lead sulphide is correct. Therefore, Statement-II is true.
So both Statement-I and Statement-II are true.
The solution marks the correct option as C, but the chemical working shown there establishes that both statements are true. Hence there is a discrepancy between the marked option and the stated chemistry. The option most defensible from the working and question text is D.