MCQEasyJEE 2024Molecular Speeds (rms, Average, Most Probable)

JEE Physics 2024 Question with Solution

At which temperature does the r.m.s. velocity of a hydrogen molecule equal that of an oxygen molecule at 47C47^\circ \text{C}?

  • A

    80K80 \, \text{K}

  • B

    73K-73 \, \text{K}

  • C

    4K4 \, \text{K}

  • D

    20K20 \, \text{K}

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: The r.m.s. velocity of hydrogen equals that of oxygen at 47C47^\circ \text{C}.

Find: The temperature of hydrogen.

Using the formula for root mean square velocity,

vrms=3RTMv_{\text{rms}} = \sqrt{\frac{3RT}{M}}

For equal r.m.s. velocities of hydrogen and oxygen,

3RTH2MH2=3RTO2MO2\sqrt{\frac{3RT_{\mathrm{H}_2}}{M_{\mathrm{H}_2}}} = \sqrt{\frac{3RT_{\mathrm{O}_2}}{M_{\mathrm{O}_2}}}

Detailed Working

Squaring both sides,

3RTH2MH2=3RTO2MO2\frac{3RT_{\mathrm{H}_2}}{M_{\mathrm{H}_2}} = \frac{3RT_{\mathrm{O}_2}}{M_{\mathrm{O}_2}}

Cancelling 3R3R,

TH2=TO2×MH2MO2T_{\mathrm{H}_2} = T_{\mathrm{O}_2} \times \frac{M_{\mathrm{H}_2}}{M_{\mathrm{O}_2}}

Now convert the oxygen temperature to Kelvin:

TO2=47+273=320KT_{\mathrm{O}_2} = 47 + 273 = 320 \, \text{K}

Using MH2=2M_{\mathrm{H}_2} = 2 and MO2=32M_{\mathrm{O}_2} = 32,

TH2=320×232=20KT_{\mathrm{H}_2} = 320 \times \frac{2}{32} = 20 \, \text{K}

Therefore, the temperature is 20K20 \, \text{K} and the correct option is D. The solution states option C, but its working clearly gives 20K20 \, \text{K}, which matches option D.

Common mistakes

  • Using the Celsius temperature directly in the r.m.s. formula is incorrect because gas-kinetic formulas require absolute temperature. Convert 47C47^\circ \text{C} to 320K320 \, \text{K} first.

  • Taking the mass ratio inversely is a common error. Since vrmsT/Mv_{\text{rms}} \propto \sqrt{T/M}, equal velocities give TMT \propto M here, so use MH2MO2\frac{M_{\mathrm{H}_2}}{M_{\mathrm{O}_2}}, not the reverse.

  • Confusing molecular mass with atomic mass leads to wrong substitution. Hydrogen gas is H2\mathrm{H}_2 with mass 22, and oxygen gas is O2\mathrm{O}_2 with mass 3232.

Practice more Molecular Speeds (rms, Average, Most Probable) questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step — free to start.

Related questions