Let the latus rectum of the hyperbola x²/9 - y²/b² = 1 subtend an… | JEE Main 2024 Mathematics PYQ

NVAMediumJEE Main 2024 · 30 January, Shift 1Conic Sections (Parabola, Ellipse, Hyperbola)

Let the latus rectum of the hyperbola $\frac{x^2}{9} - \frac{y^2}{b^2} = 1$ subtend an angle of $\frac{\pi}{3}$ at the center of the hyperbola. If $b^2$ is equal to $\frac{l}{m}(1+\sqrt{n})$ , where $l$ and $m$ are co-prime numbers, then $l^2+m^2+n^2$ is equal to:

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