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MCQMediumJEE Main 2024 · 30 January, Shift 1Linear Differential Equations

Mathematics Question from JEE Main 2024 · 30 January, Shift 1

Let y=y(x)y = y(x) be the solution of the differential equation sec⁡(x) dy+{2(1−x)tan⁡(x)+x(2−x)} dx=0\sec(x) \, dy + \{2(1 - x) \tan(x) + x(2 - x)\} \, dx = 0 such that y(0)=2y(0) = 2. Then y(2)y(2) is equal to:

  • A

    22

  • B

    2{1−sin⁡(2)}2\{1 - \sin(2)\}

  • C

    2{sin⁡(2)+1}2\{\sin(2) + 1\}

  • D

    11

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