If 50 mL of 0.5 M oxalic acid is required to neutralise 25 mL of… | JEE Main 2024 Chemistry PYQ

MCQMediumJEE Main 2024 · 29 January, Shift 2Stoichiometry & Calculations

If $50 \, \text{mL}$ of $0.5 \, \text{M}$ oxalic acid is required to neutralise $25 \, \text{mL}$ of NaOH solution, the amount of NaOH in $50 \, \text{mL}$ of the given NaOH solution is:

A
$4 \, \text{g}$
B
$2 \, \text{g}$
C
$8 \, \text{g}$
D
$16 \, \text{g}$

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