MCQMediumJEE Main 2024 · 29 January, Shift 2Simple Harmonic Motion (SHM)

Physics Question from JEE Main 2024 · 29 January, Shift 2

A simple harmonic oscillator has an amplitude AA and a time period 6π6\pi seconds. Assuming the oscillation starts from its mean position, the time required by it to travel from x=Ax = A to x=32Ax = \frac{\sqrt{3}}{2} A will be πx\frac{\pi}{x} seconds, where xx is:

  • A

    33

  • B

    55

  • C

    22

  • D

    44

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