NVAMediumJEE Main 2024 · 29 January, Shift 2Definite Integrals

Mathematics Question from JEE Main 2024 · 29 January, Shift 2

If π/6π/31sin2xdx=α+β2+γ3\int_{\pi/6}^{\pi/3} \sqrt{1 - \sin 2x} \, dx = \alpha + \beta\sqrt{2} + \gamma\sqrt{3}, where α\alpha, β\beta, γ\gamma are rational numbers, then 3α+4βγ3\alpha + 4\beta - \gamma is equal to:

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