NVAEasyJEE Main 2024 · 29 January, Shift 1Magnetic Dipole & Bar Magnet

Physics Question from JEE Main 2024 · 29 January, Shift 1

The magnetic potential due to a magnetic dipole at a point on its axis situated at a distance of 20cm20 \, \text{cm} from its center is 1.5×105Tm1.5 \times 10^{-5} \, \text{Tm}. The magnetic moment of the dipole is _____Am2\_\_\_\_\_ \, \text{Am}^2. Given: μ0/4π=107Tm/A\mu_0 / 4\pi = 10^{-7} \, \text{Tm/A}

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