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NVAEasyJEE Main 2024 · 29 January, Shift 1Rolling Motion & Rotational Kinematics

Physics Question from JEE Main 2024 · 29 January, Shift 1

A cylinder is rolling down on an inclined plane of inclination 60∘60^\circ. Its acceleration during rolling down will be x3 m/s2\frac{x}{\sqrt{3}} \, \text{m/s}^2, where x=x = . (Use g=10 m/s2g = 10 \, \text{m/s}^2)

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