Physics Question from JEE Main 2024 · 29 January, Shift 1

A ball rolls off the top of a stairway with horizontal velocity $u$. The steps are $0.1 \, \text{m}$ high and $0.1 \, \text{m}$ wide. The minimum velocity $u$ with which the ball just hits the step $5$ of the stairway will be $\sqrt{x} \, \text{m/s}$, where $x =$ . (Use $g = 10 \, \text{m/s}^2$)