MCQMediumJEE Main 2024 · 29 January, Shift 1Definite Integrals

Mathematics Question from JEE Main 2024 · 29 January, Shift 1

For x(π2,π2)x \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right), if y(x)=cscx+sinxcscxsecx+tanxsin2xdxy(x) = \int \frac{\csc x + \sin x}{\csc x \sec x + \tan x \sin^2 x}\, dx and limx(π2)y(x)=0\lim_{x \to \left(\frac{\pi}{2}\right)^-} y(x) = 0, then y(π4)y\left(\frac{\pi}{4}\right) is equal to:

  • A

    tan1(12)\tan^{-1}\left(\frac{1}{\sqrt{2}}\right)

  • B

    (12)tan1(12)\left(\frac{1}{2}\right) \tan^{-1}\left(\frac{1}{\sqrt{2}}\right)

  • C

    (12)tan1(12)-\left(\frac{1}{\sqrt{2}}\right) \tan^{-1}\left(\frac{1}{\sqrt{2}}\right)

  • D

    (12)tan1(12)\left(\frac{1}{\sqrt{2}}\right) \tan^{-1}\left(-\frac{1}{2}\right)

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