MCQMediumJEE Main 2024 · 29 January, Shift 1Conic Sections (Parabola, Ellipse, Hyperbola)

Mathematics Question from JEE Main 2024 · 29 January, Shift 1

Let (5,a4)\left(5, \frac{a}{4}\right) be the circumcenter of a triangle with vertices A(a,2)A(a, -2), B(a,6)B(a, 6), and C(a4,2)C\left(\frac{a}{4}, -2\right). Let α\alpha denote the circumradius, β\beta the area, and γ\gamma the perimeter of the triangle. Then α+β+γ\alpha + \beta + \gamma is:

  • A

    6060

  • B

    5353

  • C

    6262

  • D

    3030

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