NVAEasyJEE 2024Electronegativity & Dipole Moment

JEE Chemistry 2024 Question with Solution

The number of non-polar molecules from the following is:

Answer

Correct answer:4

Step-by-step solution

Standard Method

Given: A list of molecules is to be checked for polarity.

Find: The number of non-polar molecules.

A molecule is non-polar when its net dipole moment is zero, usually because bond dipoles cancel due to symmetry.

From the solution:

  • HF: Polar due to significant electronegativity difference.
  • H2OH_2O: Polar because of bent shape.
  • SO2SO_2: Polar because of bent shape.
  • H2H_2: Non-polar because it is made of identical atoms.
  • CO2CO_2: Non-polar because linear geometry cancels bond dipoles.
  • CH4CH_4: Non-polar because tetrahedral symmetry cancels dipoles.
  • NH3NH_3: Polar because trigonal pyramidal shape gives net dipole.
  • HCl: Polar due to electronegativity difference.
  • CHCl3CHCl_3: Polar because the molecule is asymmetric.
  • BF3BF_3: Non-polar because trigonal planar symmetry cancels dipoles.

Thus, the non-polar molecules are H2H_2, CO2CO_2, CH4CH_4, and BF3BF_3.

So, the total number of non-polar molecules is

44

Therefore, the required answer is 44.

Symmetry-Based Elimination

Given: The molecules must be classified as polar or non-polar.

Find: How many have zero net dipole moment.

Why this works: A quick way is to identify molecules with high symmetry or identical bonded atoms, because such structures often have complete dipole cancellation.

Using this idea:

  • H2H_2 is non-polar.
  • CO2CO_2 is linear and symmetric, so non-polar.
  • CH4CH_4 is tetrahedral and symmetric, so non-polar.
  • BF3BF_3 is trigonal planar and symmetric, so non-polar.

The remaining listed molecules have either bent, pyramidal, or asymmetric structures, so they are polar.

Hence, the number of non-polar molecules is 44.

Common mistakes

  • Mistake: Treating every molecule with polar bonds as polar. Why it is wrong: Molecular polarity depends on the net dipole moment, not just the presence of polar bonds. What to do instead: Check the geometry and see whether the bond dipoles cancel.

  • Mistake: Marking CO2CO_2 as polar because each C=OC=O bond is polar. Why it is wrong: The molecule is linear, so the two bond dipoles are equal and opposite. What to do instead: Evaluate the vector cancellation of dipoles in the full molecule.

  • Mistake: Assuming CHCl3CHCl_3 is non-polar because it looks tetrahedral like CH4CH_4. Why it is wrong: Tetrahedral shape alone is not enough; the substituents are not identical, so dipoles do not cancel. What to do instead: Check whether the surrounding atoms are symmetrically identical.

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