MCQEasyJEE 2024Oxidation Number & Redox Reactions

JEE Chemistry 2024 Question with Solution

Which of the following cannot function as an oxidising agent?

  • A

    N3\mathrm{N}^{3-}

  • B

    SO42\mathrm{SO}_{4}^{2-}

  • C

    BrO3\mathrm{BrO}_{3}^{-}

  • D

    MnO4\mathrm{MnO}_{4}^{-}

Answer

Correct answer:A

Step-by-step solution

Standard Method

Given: We must identify which species cannot act as an oxidising agent.

Find: The option that cannot undergo reduction further and therefore cannot behave as an oxidising agent.

An oxidising agent accepts electrons and gets reduced. So a species already having its central atom in the lowest possible oxidation state cannot act as an oxidising agent.

For N3\mathrm{N}^{3-}, nitrogen is already in its lowest possible oxidation state, 3-3. Therefore, it cannot be reduced further.

Species such as BrO3\mathrm{BrO}_{3}^{-} and MnO4\mathrm{MnO}_{4}^{-} are well-known oxidising agents because Br and Mn are in high oxidation states and can gain electrons by reduction.

Therefore, the substance that cannot function as an oxidising agent is N3\mathrm{N}^{3-}. Hence, the correct option is A.

The solution incorrectly labels the option letter as C, but the worked conclusion identifies N3\mathrm{N}^{3-}, which corresponds to option A in the given options.

Oxidation State Basis

Given: The options are N3\mathrm{N}^{3-}, SO42\mathrm{SO}_{4}^{2-}, BrO3\mathrm{BrO}_{3}^{-}, and MnO4\mathrm{MnO}_{4}^{-}.

Find: Which one cannot act as an oxidising agent.

An oxidising agent must be capable of accepting electrons. That means the relevant atom should be able to move to a lower oxidation state.

In N3\mathrm{N}^{3-}, nitrogen has oxidation state 3-3, which is the minimum oxidation state of nitrogen. Since it cannot go below 3-3, it cannot accept electrons further.

Thus N3\mathrm{N}^{3-} cannot act as an oxidising agent, whereas the other species contain atoms in relatively higher oxidation states and can undergo reduction.

Therefore, the correct option is A.

Common mistakes

  • Mistake: Choosing a species with a high negative charge as automatically non-oxidising without checking oxidation state. Why wrong: charge alone does not decide oxidising behaviour. What to do instead: determine the oxidation state of the relevant atom and check whether further reduction is possible.

  • Mistake: Trusting the printed option letter in the solution without matching it to the actual option text. Why wrong: the solution contains a letter mismatch. What to do instead: use the worked conclusion N3\mathrm{N}^{3-} and map it to the listed options carefully.

  • Mistake: Confusing oxidising agent with reducing agent. Why wrong: an oxidising agent gets reduced by accepting electrons, while a reducing agent gets oxidised by donating electrons. What to do instead: first identify whether the species must gain or lose electrons in the process.

Practice more Oxidation Number & Redox Reactions questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step — free to start.

Related questions