NVAEasyJEE Main 2024 · 27 January, Shift 1Simple Harmonic Motion (SHM)

Physics Question from JEE Main 2024 · 27 January, Shift 1

A particle executes simple harmonic motion with an amplitude of 4cm4 \, \text{cm}. At the mean position, the velocity of the particle is 10cm/s10 \, \text{cm/s}. The distance of the particle from the mean position when its speed becomes 5cm/s5 \, \text{cm/s} is α\sqrt{\alpha} cm, where α=\alpha = ?

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