The function defined by highest prime factor of , is:
- A
one-one and onto
- B
one-one only
- C
onto only
- D
neither one-one nor onto
The function defined by highest prime factor of , is:
one-one and onto
one-one only
onto only
neither one-one nor onto
Correct answer:D
Standard Method
Given: The function is where is the highest prime factor of .
Find: Whether the function is one-one, onto, both, or neither.
To test whether is one-one, consider two different inputs:
Both and have the same image . Therefore, different elements of the domain map to the same value, so is not one-one.
To test whether is onto, note that the codomain is , but the output of is always a prime number because it is the highest prime factor of .
Hence a natural number such as cannot be the image of any , since is not prime. So every element of is not attained. Therefore, is not onto.
Therefore, the function is neither one-one nor onto. The correct option is D.
Step-by-Step Check
Given: returns the highest prime factor of for .
Find: The nature of the function.
Examples from the definition:
These show that the output is always a prime number.
For injectivity, if the function were one-one, distinct inputs would have distinct outputs. But
so is not injective.
For surjectivity, every element of should appear as an output. Since only prime numbers can occur as values of , composite numbers such as are never attained. Thus is not surjective.
So the function is neither one-one nor onto, hence the correct option is D.
Assuming the function is one-one because each number has a unique highest prime factor. This is wrong because one-one concerns distinct inputs having distinct outputs. Different numbers such as and can have the same highest prime factor. Check images of different inputs, not uniqueness of factorization.
Assuming the function is onto because every prime number appears as an output. This is wrong because the codomain is , not the set of primes. To test onto, every natural number must be attained; composite numbers like are not outputs.
Confusing the domain and codomain while testing surjectivity. The domain is , but onto must be checked against the codomain . Always compare the range with the codomain, not with the domain.
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