MCQMediumJEE Main 2024 · 27 January, Shift 1Conic Sections (Parabola, Ellipse, Hyperbola)

Mathematics Question from JEE Main 2024 · 27 January, Shift 1

The length of the chord of the ellipse x225+y216=1\frac{x^2}{25} + \frac{y^2}{16} = 1, with midpoint (1,25)\left(1, \frac{2}{5}\right), is:

  • A

    16915\frac{\sqrt{1691}}{5}

  • B

    20095\frac{\sqrt{2009}}{5}

  • C

    17415\frac{\sqrt{1741}}{5}

  • D

    15415\frac{\sqrt{1541}}{5}

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Conic Sections (Parabola, Ellipse, Hyperbola) questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions