MCQMediumJEE 2024Continuity

JEE Mathematics 2024 Question with Solution

Consider f(x)=a(7x12x2),bx27x+12f(x)= a(7x-12-x^2), b \lvert x^2-7x+12 \rvert for continuity. Find n(S)n(S).

  • A

    22

  • B

    Infinitely many

  • C

    44

  • D

    11

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: The function is defined using the expressions a(7x12x2)a(7x-12-x^2) and bx27x+12b\lvert x^2-7x+12 \rvert, and continuity is required.

Find: n(S)n(S), the number of ordered pairs in the set SS.

From the extracted solution, solving the continuity condition at x=3x=3 gives the unique solution

(a,b)=(4,2)(a,b)=(-4,2)

Hence the set SS contains exactly one element.

Therefore, the correct option is D and n(S)=1n(S)=1.

Common mistakes

  • Treating continuity at only one point as giving multiple valid pairs. This is wrong because the extracted solution states that the continuity condition leads to a unique pair (a,b)=(4,2)(a,b)=(-4,2). Always use the continuity equations to determine whether the solution is unique or not.

  • Ignoring the modulus expression x27x+12\lvert x^2-7x+12 \rvert while analysing continuity. This is wrong because modulus-based expressions can change form at the zeros of the quadratic. Check the critical points before concluding the number of valid parameter pairs.

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