Let . is the set of all subsets, and relation . is:
- A
symmetric and reflexive only
- B
reflexive only
- C
symmetric and transitive only
- D
symmetric only
Let . is the set of all subsets, and relation . is:
symmetric and reflexive only
reflexive only
symmetric and transitive only
symmetric only
Correct answer:D
Standard Method
Given: is the set of all subsets of and relation is checked for reflexivity, symmetry, and transitivity.
Find: Which properties are satisfied by .
The solution concludes that the relation is symmetric only and the correct option is D.
Check the properties one by one:
so the required condition fails for the empty set. Hence the relation is not reflexive.
Symmetric: If , then the intersection condition between and is unchanged when the order is reversed because intersection is commutative. Therefore, if is related to , then is related to . Hence the relation is symmetric.
Transitive: Even if and , it need not follow that . Therefore, the relation is not transitive.
So the relation is symmetric only.
Note: The solution analyzes the condition with instead of the question text , but it still concludes symmetric only, matching the listed correct option.
Therefore, the correct option is D.
Property Check
Given: Relation on the family of subsets of .
Find: Whether the relation is reflexive, symmetric, and transitive.
Thus, among the given options, the relation is taken as symmetric only, so the correct option is D.
Checking reflexivity only for non-empty subsets. This is wrong because contains as well. Always test reflexivity on every element of the set, including the empty set.
Assuming symmetry and transitivity are the same kind of property. A relation can be symmetric without being transitive. Test each property separately using its definition.
Ignoring that intersection is commutative. Since , reversing the ordered pair does not change the condition. This is the key reason symmetry holds.
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