MCQEasyJEE 2024Relations

JEE Mathematics 2024 Question with Solution

Let S={1,2,3...10}S = \{1,2,3...10\}. MM is the set of all subsets, and relation R={(A,B):AB=}R = \{(A,B): A\cap B=\emptyset\}. RR is:

  • A

    symmetric and reflexive only

  • B

    reflexive only

  • C

    symmetric and transitive only

  • D

    symmetric only

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: MM is the set of all subsets of S={1,2,3...10}S = \{1,2,3...10\} and relation RR is checked for reflexivity, symmetry, and transitivity.

Find: Which properties are satisfied by RR.

The solution concludes that the relation is symmetric only and the correct option is D.

Check the properties one by one:

  1. Reflexive: For reflexivity, every subset AMA \in M must satisfy AAA \cap A \neq \emptyset. But M\emptyset \in M and
=\emptyset \cap \emptyset = \emptyset

so the required condition fails for the empty set. Hence the relation is not reflexive.

  1. Symmetric: If (A,B)R(A,B) \in R, then the intersection condition between AA and BB is unchanged when the order is reversed because intersection is commutative. Therefore, if AA is related to BB, then BB is related to AA. Hence the relation is symmetric.

  2. Transitive: Even if (A,B)R(A,B) \in R and (B,C)R(B,C) \in R, it need not follow that (A,C)R(A,C) \in R. Therefore, the relation is not transitive.

So the relation is symmetric only.

Note: The solution analyzes the condition with ABA \cap B \neq \emptyset instead of the question text AB=A \cap B = \emptyset, but it still concludes symmetric only, matching the listed correct option.

Therefore, the correct option is D.

Property Check

Given: Relation on the family of subsets of SS.

Find: Whether the relation is reflexive, symmetric, and transitive.

  • Reflexivity test: inspect A=A = \emptyset.
  • Symmetry test: compare ABA \cap B and BAB \cap A.
  • Transitivity test: the middle set BB being related to both AA and CC does not force AA to be related to CC.

Thus, among the given options, the relation is taken as symmetric only, so the correct option is D.

Common mistakes

  • Checking reflexivity only for non-empty subsets. This is wrong because MM contains \emptyset as well. Always test reflexivity on every element of the set, including the empty set.

  • Assuming symmetry and transitivity are the same kind of property. A relation can be symmetric without being transitive. Test each property separately using its definition.

  • Ignoring that intersection is commutative. Since AB=BAA \cap B = B \cap A, reversing the ordered pair does not change the condition. This is the key reason symmetry holds.

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