MCQMediumJEE Main 2024 · 27 January, Shift 1Conic Sections (Parabola, Ellipse, Hyperbola)

Mathematics Question from JEE Main 2024 · 27 January, Shift 1

If the shortest distance of the parabola y2=4xy^2 = 4x from the centre of the circle x2+y24x16y+64=0x^2 + y^2 - 4x - 16y + 64 = 0 is dd, then d2d^2 is equal to:

  • A

    1616

  • B

    2424

  • C

    2020

  • D

    3636

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