MCQMediumJEE Main 2023 · 13 April, Shift 2Cross Product

Mathematics Question from JEE Main 2023 · 13 April, Shift 2

Let ∣a⃗∣=2|\vec{a}| = 2, ∣b⃗∣=3|\vec{b}| = 3 and the angle between the vectors a⃗\vec{a} and b⃗\vec{b} be π4\frac{\pi}{4}. Then ∣(a⃗+2b⃗)×(2a⃗−3b⃗)∣2\left|\left(\vec{a} + 2\vec{b}\right) \times \left(2\vec{a} - 3\vec{b}\right)\right|^2 is equal to:

  • A

    482482

  • B

    841841

  • C

    882882

  • D

    441441

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Cross Product questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions