MCQMediumJEE Main 2023 · 13 April, Shift 2Cross Product

Mathematics Question from JEE Main 2023 · 13 April, Shift 2

Let a=2|\vec{a}| = 2, b=3|\vec{b}| = 3 and the angle between the vectors a\vec{a} and b\vec{b} be π4\frac{\pi}{4}. Then (a+2b)×(2a3b)2\left|\left(\vec{a} + 2\vec{b}\right) \times \left(2\vec{a} - 3\vec{b}\right)\right|^2 is equal to:

  • A

    482482

  • B

    841841

  • C

    882882

  • D

    441441

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